Accessing values inside a returned array

Question

I am working with truffle and failing to get the actual values from my return:

[ [ { [String: '10'] s: 1, e: 1, c: [Object] },
    { [String: '35'] s: 1, e: 1, c: [Object] },
    { [String: '40'] s: 1, e: 1, c: [Object] },
    { [String: '50'] s: 1, e: 1, c: [Object] },
    { [String: '60'] s: 1, e: 1, c: [Object] } ],
  [ { [String: '20'] s: 1, e: 1, c: [Object] },
    { [String: '35'] s: 1, e: 1, c: [Object] },
    { [String: '40'] s: 1, e: 1, c: [Object] },
    { [String: '50'] s: 1, e: 1, c: [Object] },
    { [String: '60'] s: 1, e: 1, c: [Object] } ] ]

I tried result.valueOf()[0][0].toString() but that didn't do the trick.

However, result.valueOf()[0].toString() is working on the following example:

[ [ { [String: '10'] s: 1, e: 1, c: [Object] } ],
  [ { [String: '20'] s: 1, e: 1, c: [Object] } ] ]

Any help would be appreciated!

EDIT: The goal is to use the values for a test, ideally somehow like that:

 assert.equal(result.valueOf()[0][0].toString(), [10, 35, 40, 50, 60]);
 assert.equal(result.valueOf()[1][0].toString(), [20, 35, 40, 50, 60]);

EDIT2: The values that the contract returns are (uint256[], uint256[])

Cheers! carbee

Answer 1

If you are just expecting an array return, try console.logging: result.args.c, result.args.c[0]

The actual response usually ends up in c.

---

Update #1

If you were getting a return of arrays, then your overall response should be something like (with BigNumber instead of String):

[ [ BigNumber { s: 1, e: 0, c: [Array] },
    BigNumber { s: 1, e: 0, c: [Array] } ],
  [ BigNumber { s: 1, e: 0, c: [Array] },
    BigNumber { s: 1, e: 0, c: [Array] } ] ]

From that, you have to map the array in order to make the array desired:

let arr = result.map(res => {
  return res.map(res => res.c[0])
})

You should get the array you want with arr.

Since c in your case is an [Object], you'd have to see what is in that object and replace res.c[0] with the map to that object value you want. I assume its .value...but I don't have code to verify that right now. Hopefully this helps.

And just for reference result.valueOf()[0][0].toString() would actually be result.valueOf()[0].c[0].toString().