How come it's okay to assign multiple times to an immutable variable?

Question

Note - Following is a contract that successfully compiled.

In this contract's constructor, I have clearly assigned multiple times to x. Why is this okay? What's happening here?

// SPDX-License-Identifier: MIT
pragma solidity 0.8.26;

contract IsThisImmutable {

    uint public s_a = 0;

    uint256 public immutable x;

    constructor() {
        x = 134;
        x += 3;
        s_a += x;
        x += 3;
    }

    function exp1(uint256 a) public returns(uint256) {
        s_a += a;
        s_a += x;
        return 34;
    }

    modifier modifier1 {
        _;
        s_a += 1023;
        return;
    }


}

Answer 1

It’s okay because you’re assigning value to x multiple times within the constructor itself, so the state change is only considered one time i.e., the final value that’s being assigned to it in the constructor.