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I have a 2D Array uint[][100] myArray. I want to access the length of the first dimension (the dynamic array). Therefore I use myArray.length, but then I get the value 100 the length of the second dimension (the static array).

How can I get the the length of the first dimension?

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  • myArray[0].length obviously
    – goodvibration
    Jun 20, 2020 at 8:16
  • And of course, there is no such thing "the length of the first dimension" here, since each one of your 100 sub-arrays may have a different length.
    – goodvibration
    Jun 20, 2020 at 8:23
  • At myArray[0].length I would expect 100
    – wero026
    Jun 20, 2020 at 8:56
  • Does Solidity specifiy multi dimensional arrays in reverse order than other programming languages do, like C or Java? Normally I would expect that myArray.length gives the length of the dynamic part and myArray[0].length of the static part, that is 100.
    – wero026
    Jun 20, 2020 at 9:01
  • No, 100 is myArray.length. At myArray[0].length you should expcet however many elements you've pushed there.
    – goodvibration
    Jun 20, 2020 at 9:17

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After reading the docs (which should be done before posting here ;) ) I found out that the specification of multi dimensional arrays in Solidity are in reverse order than it is in other programming languages, like C or Java.

So uint[][100] myArray would be 100 arrays of dynamic sized uint arrays. And myArray.length would be of course 100.

But what I actually want was uint[100][] myArray. A dynamic array within of each an array of 100 uints. Then myArray.length gives me the size of the dynamic array.

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