4

I know I can get the current nonce using eth.getTransactionCount(address), but I'm looking for something like eth.getTransaction(address, nonce) (for arbitrary nonce), similarly to eth.getTransactionFromBlock(blockHashOrNumber, index).

An alternative would be to get all (perhaps just recent) transactions that originated from an address.

9

You must lookup all transactions made by an account and retrieve the transaction for the nonce you're interested in:

function getTransactionsByAccount(myaccount, startBlockNumber, endBlockNumber, nonce) {
  if (endBlockNumber == null) {
    endBlockNumber = eth.blockNumber;
    console.log("Using endBlockNumber: " + endBlockNumber);
  }
  if (startBlockNumber == null) {
    startBlockNumber = endBlockNumber - 1000;
    console.log("Using startBlockNumber: " + startBlockNumber);
  }
  console.log("Searching for transactions to/from account \"" + myaccount + "\" within blocks "  + startBlockNumber + " and " + endBlockNumber);

  for (var i = startBlockNumber; i <= endBlockNumber; i++) {
    if (i % 1000 == 0) {
      console.log("Searching block " + i);
    }
    var block = eth.getBlock(i, true);
    if (block != null && block.transactions != null) {
      block.transactions.forEach( function(e) {
        if (myaccount == e.from && nonce == e.transactionIndex) {
          // Do something with the trasaction
          console.log("  tx hash          : " + e.hash + "\n"
            + "   nonce           : " + e.nonce + "\n"
            + "   blockHash       : " + e.blockHash + "\n"
            + "   blockNumber     : " + e.blockNumber + "\n"
            + "   transactionIndex: " + e.transactionIndex + "\n"
            + "   from            : " + e.from + "\n" 
            + "   to              : " + e.to + "\n"
            + "   value           : " + e.value + "\n"
            + "   time            : " + block.timestamp + " " + new Date(block.timestamp * 1000).toGMTString() + "\n"
            + "   gasPrice        : " + e.gasPrice + "\n"
            + "   gas             : " + e.gas + "\n"
            + "   input           : " + e.input);
        }
      })
    }
  }
}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.