Is it possible to store an array of bytes (so something like bytes[])?

Question

Edit

The original question below seems to work as expected. The issue happens with the call return data is empty. When the response is nothing, the code below fails.

The following works, but is there a better way to do it?

bytes[] memory val;
for(uint i = 0; i < item.length; i++) {
    (, bytes memory response) = addr.call.value(_value[i])(_data);
    if (response.length != 0) {
        val[i] = response;
    }
}

---

I am unable to figure out how to store an array of bytes. I understand that bytes is an array of byte1s, but I want to be able to store multiple bytes in an array? So ideally, I would be able to define bytes[], where each member of that array is a new bytes.

Some example code (which is not working) is:

bytes[] memory val;
for(uint i = 0; i < _value.length; i++) {
    (, bytes memory response) = addr.call.value(_value[i])(_data);
    val[i] = response;
}

This is reverting on val[i] = response;. Does anyone know why?

Answer 1

You should by the least add another internal for loop in your code.

Something like this:

bytes[] memory val = new bytes[](_value.length);
for (uint i = 0; i < _value.length; i++) {
    (bool success, bytes memory response) = addr.call.value(_value[i])(_data);
    require(success, "call failed");
    val[i] = new bytes(response.length);
    for (uint j = 0; j < response.length; j++) {
        val[i][j] = response[j];
    }
}