0

I want to find ethereum address and I have almost all the letters. The beginning of the wallet: 0xb6b2ceb624a6b667e67af1893b16706baec21 But how can I find remaining letters?

3 Answers 3

1

Code using web3.js 1.0-beta, which failed to find any accounts with positive balances:

const Web3 = require('web3');
const web3 = new Web3('https://mainnet.infura.io');

const start = '0xb6b2ceb624a6b667e67af1893b16706baec21';

async function main() {
    for (var i = 0; i < 4096; i++) {
        const end = web3.utils.padLeft(web3.utils.toHex(i).substring(2), 3);
        const address = start + end;
        const balance = parseInt(await web3.eth.getBalance(address), 10);

        if (balance > 0) {
            console.log(`${address} has a balance of ${balance} wei.`);
        }
    }
}

main();
1

You have 3 digits missing and all the possible combinaisons are valid address from 0xb6b2ceb624a6b667e67af1893b16706baec21000 (here) to 0xb6b2ceb624a6b667e67af1893b16706baec21fff (here)

You have no choice than checking all the combinaisons: 16^3 = 4096

If you are sure that the address you are looking for has a positive balance, you can write an algorithm which will check for each possible combinaison the balance and extract only the address with positive balance.

For example:

const provider     = new Web3.providers.HttpProvider("https://mainnet.infura.io/");
const web3         = new Web3(provider);

const alphabet = [0,1,2,3,4,5,6,7,8,9,a,b,c,d,e,f];
const input = "0xb6b2ceb624a6b667e67af1893b16706baec21";

for (x in alphabet) { 
    for (y in alphabet) {
        for (z in alphabet) {
            let address = input + x + y + z;
            let balance = new BigNumber(web3.eth.getBalance(address));

            if(balance.greaterThan(new BigNumber(0)) {
               console.log(address + "=" + web3.fromWei(balance, "ether"));
            }
        }
    }
}
1
  • I ran something similar and didn't find any accounts with positive balances.
    – user19510
    Jan 24, 2019 at 9:36
0

You can write SQL query using LIKE syntax with wildcard character %.

SELECT *
FROM ethereum.transactions
WHERE TO_ADDRESS LIKE '0xb6b2ceb624a6b667e67af1893b16706baec21%'

See it in action on Flipside.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.