How to map multiple time and index value on same address

Question

I wish to map the time to the address key. But currently it is working on the index key only. I just want to map time as well. Means the current time. So that I can able to get the record with time as well.

pragma solidity ^0.4.17;

contract Experment2 {
uint public creationTime = now;
struct Record {
  // address owner;
   //uint id;
   string name;
   string senderaddress;
   string reciveraddress;
   string scheduletime;
   string scheduledate;
  // uint Index;
   uint time;
}
mapping (uint => Record[]) records;


function setRec (uint id, string name, string senderaddress, string reciveraddress, string scheduletime, string scheduledate, uint time) public {
     records[id].push(Record(name, senderaddress, reciveraddress, scheduletime, scheduledate, time =now));
}

function getrec(uint id , uint index) constant returns(string, string, string, string, string, uint){ {
    var a = records[id][index].name;
    var b = records[id][index].senderaddress;
    var c = records[id][index].reciveraddress;
    var d = records[id][index].scheduletime;
    var e = records[id][index].scheduledate;
    var f = records[id][index].time;

}
return(a,b,c,d,e,f);
}


function get_last_ten(uint id) constant returns (uint[10]){
    //uint[10] memory lastItem1;
    uint[10] memory lastItem2;
    for(uint i=0;i<10;i++){
        if(records[id].length>i){
          //  lastItem1[i] = records[id][records[id].length-i-1].index;
            lastItem2[i] = records[id][records[id].length-i-1].time;
        }
    }
    return (lastItem2);
}
}

Like in the above code the mapping is only through with index value. I can onl manage to return the current time. But I want to map the data on time as well.

So that I can run

function getrec(uint id , uint time) constant returns(string, string, string, string, string, uint){ {
    var a = records[id][time].name;
    var b = records[id][time].senderaddress;
    var c = records[id][time].reciveraddress;
    var d = records[id][time].scheduletime;
    var e = records[id][time].scheduledate;
    var f = records[id][time].time;

}
return(a,b,c,d,e,f);
}

Answer 1

You can use an indirect index from id to time to index (to simplify I'd assume time are not repeated).

mapping (uint => mapping (uint => uint)) recordIndex;

Then you can access a record from time using the index obtained.

function getrec(uint id , uint time) view returns (string, string, string, string, string, uint) {
    uint index = recordIndex[id][time];
    // We use index = 0 to indicate an invalid time
    require(index > 0, "invalid time");
    index -= 1;
    string a = records[id][index].name;
    string b = records[id][index].senderaddress;
    string c = records[id][index].reciveraddress;
    string d = records[id][index].scheduletime;
    string e = records[id][index].scheduledate;
    uint f = records[id][index].time;

    return (a, b, c, d, e, f);
}

Now when adding a new record you also have to update the index.

function setRec (uint id, string name, string senderaddress, string reciveraddress, string scheduletime, string scheduledate, uint time) public {
     uint index = records[id].push(Record(name, senderaddress, reciveraddress, scheduletime, scheduledate, time =now));
     // push returns the length of the array
     // or equivalently position+1
     recordIndex[id][now] = index;
}

You probaly can solve the problem of records with duplicated times if you use an array to store indexes.