Code Explanation of how to return an array of structs

Question

I was reading a tutorial on a medium about how to return an array of structs. This is the code they have for doing it.

pragma solidity ^0.4.13;

contract Project
{
    struct Person {
        address addr;
        uint funds;
    }

    Person[] people;

    function getPeople(uint[] indexes)
        public
        returns (address[], uint[])
    {
        address[] memory addrs = new address[](indexes.length);
        uint[]    memory funds = new uint[](indexes.length);

        for (uint i = 0; i < indexes.length; i++) {
            Person storage person = people[indexes[i]];
            addrs[i] = person.addr;
            funds[i] = person.funds;
        }

        return (addrs, funds);
    }
}

The uint[] index argument however makes no sense to me. Can someone please explain what it is and what it does?

Answer 1

uint[] indexes is used to access the data of people located at the indices passed to the function, to build an array of structs to return.

For example: if there were 100 Person stored in the contract, and we wanted an array of just the Person's stored at [1, 2, 3], we pass that array as uint[] indexes and receive the addresses and funds located at people[1], people[2], and people[3].