# Quorum IBFT - PBFT - BFT - 3F + 1 / 3M + 1

Understand that Quorum supports IBFT. Am trying to decide what is the suitable number of nodes to setup up to support X number of byzantine nodes. Using PBFT formula, 3F + 1, I am trying to come out with the number of nodes is required.

E.g., 3F + 1

Assuming 1 byzantine node, is it 3(1) + 1 = 4 nodes to have as minimum no. of nodes nodes count or 4 honest nodes plus 1 malicious nodes, i.e., total of 5 nodes?

Assuming 2 byzantine nodes , is it 3(2) + 1 = 7 nodes to have as minimum no. of nodes count or 7 honest nodes plus 2 malicious nodes, i.e., total of 9 nodes?

Assuming 3 byzantine nodes, is it 3(3) + 1 = 10 nodes to have as minimum no. of nodes count or 10 nodes plus 3 malicious nodes, i.e., total of 13 nodes?

Is it the former or latter count?

• I've edited your question to remove the signature. Please do not tag posts with a signature, as this simply unnecessarily clutters the question (Your name and profile appear below the post already). Please see meta.stackexchange.com/questions/5029/… Jul 6, 2018 at 17:09