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I have a payable function that transfers ether to contract.

function test(...) public payable returns (bool) {  
    ...                                                                                               
    address(this).transfer(msg.value); 

    return true;
}

I found that above method fails without having a fallback function in the contract.

function () payable public {}

Can anyone explain this please?

1 Answer 1

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Because the line address(this).transfer(msg.value); is transferring msg.value worth of Ether from the contract to itself.

And if you send Ether to a contract without a payable fallback function it will fail.

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  • so whenever I want to send ether to a contract I must have a fallback function?
    – bbusdriver
    May 18, 2018 at 9:27
  • Im not sure what version of solidity it started in, but by default if you dont have a payable fallback function you can't just send ETH to that contract. (This doesn't include other payable functions). But the line address(this).transfer(msg.value); is redundant anyway, the entire msg.value automatically goes to the contract, you don't have to manually set it. May 18, 2018 at 9:31

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