11

I'm working on a puzzle where msg.sender != tx.origin, so the implication is that the caller needs to be a contract or at least something in between the calling account.

But extcodesize(caller) == 0 also needs to be true. So the caller needs to be an address or externally owned account.

How can both of these be true? Can the caller's codesize ever be 0 if not an address/EOA?

4
  • Is caller msg.sender? Apr 8, 2018 at 17:38
  • Should be. caller is assembly so is not loggable. But caller is the calling contract, or at least typically it is.
    – Joe Blow
    Apr 8, 2018 at 17:46
  • Yeah I was just wondering, no idea what the caller really means. Apr 8, 2018 at 17:50
  • Actually, by the documentation, it's not the "call sender" in case of delegatecall. That might be a part of the solution. But don't ask me how. Apr 8, 2018 at 17:52

1 Answer 1

12

All things must have a beginning

I think you're getting called from a contract constructor before it's committed to the chain.

At this point, it will have a (theoretical) address but no code yet in the chain. It will only get code size after the transaction completes and the block is accepted.

1
  • 1
    If this answered your question, please mark it as the correct answer. If not let me know so I can further assist.
    – supakaity
    Apr 10, 2018 at 9:41

This site is temporarily in read-only mode and not accepting new answers.

Not the answer you're looking for? Browse other questions tagged .