It's said if we run:

suicide(address recipient);

At the end of the contract, the recipient will receive the amount of Ether owned by the contract.

Question 1: How does the contract (and this function) know where the amount of Ether is?

Question 2: In the 1st example here, they have no "suicide", then how the funding is released to the recipient (or beneficiary)?

"payable" enables a function (and contract) to receive Ether, and it can keep track of the amount it receive by using an array, e.g.

mapping (address => uint) balances;

Question 3: How does the contract claim the money it receives?


Q1) The contract simply has the ether... For example:

Try this.balance

I'm unfamiliar with the exact assembly generated, but I would assume it does the following:

1) recipient.send(this.balance)

2) send kill opcode

It might be that it is a form of "delete" Just like delete xyz[1234] recovers some gas

Q2) Unless a function that sends beneficiary.send(this.balance) funds could essentially be locked inside a contract, there is no "magic" going on, you can write terrible contracts if you want :)

Q3) As a contract receives funds via a payable function, it just has them, it doesn't need to claim it, unless it's dealing with receiving an ERC-20 token, but that's a whole different chapter

  • 1) There's a dedicated opcode SELFDESTRUCT that does everything. – Ismael Aug 18 '17 at 14:42

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