How does Solidity/the EVM store a uint vs. an int?

Question

What's the difference, in terms of bit structure, between an int and a uint under the EVM?

For an example, if an int8's value, expressed in binary, was 00010011, what would the uint8 of that be? What would negative 00010011 look like?

Answer 1

Edition (Thanks Tjaden): when an int is negative it is represented using two's complement system in which we get for an int: 1111 1111=−1(255 for uint) whereas 0000 0001=1 (1 for uint).

For example:

uint256 u=123456789;

is represented by 0x00000000000000000000000000000000000000000000000000000000075bcd15 ( Big Endian)

and int v=-123456789; is represented by 0xfffffffffffffffffffffffffffffffffffffffffffffffffffffffff8a432eb ( Big Endian )

int w=123456789

is represented by :

"0x00000000000000000000000000000000000000000000000000000000075bcd15"