0

Suppose I'm building a transaction such as:

const raw = [
    new Buffer("0001", "hex"),
    new Buffer("23000000000", "hex"),
    new Buffer("21000", "hex"),
    new Buffer("0x00000000000000000000"),
    new Buffer("0xde0b6b3a7640000"),
    new Buffer("0x1234abcd")
]
const encoded = RLP.encode(raw);

Can I freely add/remove leading zeroes of those buffers without affecting the meaning of the message?

3

You can't. RLP can't have leading zeros. It is designed to encode values in a shortest way, so redundant leading zeros make RLP not canonical.

What's more, transaction's RLP starts with payload containing size of transaction. By prepending anything there, you simply alter/overwrite the payload and make transaction undecodable

edit.

Encoding example:

257 is encoded as 0x810101 which is

0x80 plus the length of the string followed by the string

docs: https://github.com/ethereum/wiki/wiki/RLP

| improve this answer | |
  • OK - but is that on the byte level, right? You can still have leading zeroes within a byte, i.e., 257 is still 00000001 00000001, rather than 10000001, corect? – MaiaVictor Apr 1 '17 at 17:45
  • I've added encoding example to my response ;) – debris Apr 2 '17 at 16:43
  • Note: With nonce 0x80 is not appended until nonce ≥0x80 itself. So nonce of 0x0 is 80, nonce of 0x1 is 01, nonce of 0x7f is just 7f whereas nonce 0x8f is 808f – Albert Renshaw May 15 at 20:49

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