Understanding memory type solidity in function's return type

Question

pragma solidity ^0.8.0;

contract Crud {

    struct Users{
        uint id;
        string name;
    }

    Users[] users; // this is type storage
    uint length = 0;

    function addUser(string memory _name) public{
        users.push(Users(length,_name));
        length++;
    }

    function getUser(uint _index) view public returns(Users memory){
        return users[_index];
    }
}

I have this basic code.

In getUser function why is it expecting the return type of Users as memory? It will return users and that is type storage.

Answer 1

I believe what will happen here is the function will copy the values from the Users struct from storage to memory before return. I don't believe you can return storage directly from a public view function anyway since it could go to another contract.