Dynamic in-memory array declaration and assignment in 0.8.10 [duplicate]

Question

Is it possible to assign a dynamic in-memory array during the declaration?
Like this:

uint[] memory someDynamicArr = [1,2,3];

Or the only possible way is:

uint[] memory someDynamicArr;
someDynamicArr[0] = 1;
someDynamicArr[1] = 2;
someDynamicArr[2] = 3;

Answer 1

As per documentation fixed size memory arrays cannot be assigned to dynamically-sized memory arrays, i.e. the following is not possible:

uint[] memory someDynamicArr = [1,2,3];

This will throw error because the type of [1, 2, 3] is uint8[3] memory, because the type of each of these constants is uint8. If you want the result to be a uint[3] memory type, you need to convert the first element to uint.

uint[] memory someDynamicArr = [uint(1),2,3];

Following will throw an error too, because fixed size memory arrays cannot be assigned to dynamically-sized memory arrays.

// uint[3] memory cannot be converted to uint[] memory.   
uint[] memory x = [uint(1), 3, 4];

If you want to initialize dynamically-sized arrays, you have to assign the individual elements:

// SPDX-License-Identifier: GPL-3.0
pragma solidity >=0.4.16 <0.9.0;

contract C {
    function f() public pure {
        uint[] memory x = new uint[](3);
        x[0] = 1;
        x[1] = 3;
        x[2] = 4;
    }
}