If you use '--fakepow option' in geth, what exactly happens?
The documentation in Geth says:
--fakepow Disables proof-of-work verification
Does it create a block without PoW? or does it skip the block verification?
And what is this option for?
asked Dec 21, 2016 at 17:11
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1 Answer
This flag was added in commit #2485, entitled:
"Add a
--fakepowflag to help benchmarking database changes".
From the description on the PR, it:
...allows testing and evaluating various non POW related optimizations by themselves (e.g. database opts) without having to constantly wait for the costly POWs to also run.
answered Dec 22, 2016 at 11:48
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This does not answer the question of the OP >Does it create a block without PoW? Commented Jan 23, 2017 at 10:37
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But isn't the answer to that (sub-question) implicitly "no"? :) The main question asks what the flag does. Commented Jan 23, 2017 at 13:07
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