Why isn't msg.sender.send getting called?

Question

Contract code:

function rand( uint256 seedB ) returns (uint256){ 
    
    //define seedA variable
    uint256 seedA = 1;
    
    uint amount = 1 finney;
    
    if (seedA == seedB) { 
        msg.sender.send(amount);
    }
    

    return seedA + seedB; 
}

https://gist.github.com/anonymous/e210a052b6b4c86337c2

Basically, if SeedA (which equals 1) equals SeedB it sends amount to msg.sender.

---

Why does this not work, when I am calling the function using:

random.rand.sendTransaction(1,
    {from: eth.accounts[0], 
    value: web3.toWei(.0001, 'ether'), 
    to: '0x4abc14efad9a7a84a0a9ef6e1a782c43a9e3f550', 
    gas: 500000,  data: web3.fromAscii('message')})

Here is the contract address: https://www.etherchain.org/account/0x4abc14efad9a7a84a0a9ef6e1a782c43a9e3f550

Am I invoking the contract improperly in the sendTransaction? I am invoking it from inside my local geth client.

How do I ensure my parameter (1) is passed into the contract function rand via sendTransaction?

Answer 1

In your contract you are trying to send 1 finney, but you are only providing your contract with 0.1 finney... A Finney is 0.001 ETH, not 0.0001

Answer 2

It might be because you supply data when calling sendTransaction on an actual function, overriding the function identifier and the function argument you gave (1).

Answer 3

Try web3.eth.defaultAccount = web3.eth.accounts[0]

and then random.rand.sendTransaction(1)